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2019년 03월 21일
모든 걸 다 잃고 나서야 비로소 나는, 사소한 것들의 소중함들을 깨달을 수 있게 되었다. - 바다아이
 

    golang

golang - strconv.ParseInt strconv.Atoi strconv.FormatInt strconv.Itoa 정수 문자열 변환
이 름 : 바다아이   |   조회수 : 1452         짧은 주소 : https://www.bada-ie.com/su/?631523067673
ParseInt, strconv. A string contains digit characters like "123." We can convert this string to a number, an int, with the ParseInt method.
Other options. With Atoi we have a simpler way to call ParseInt. These methods return two values: the parsed integer itself, and an error code.
Example, ParseInt. Let us begin with this simple example. We import the strconv package at the top. We call ParseInt with three arguments—the first is the string.

Argument 2:This is the base of the string being parsed. Most numbers we use are base 10.

Argument 3:This is the bit size of the resulting int. 0 means int, while 6 (for example) means int16, with 16 bits.

Based on: Golang 1.7

Golang program that uses strconv.ParseInt

package main

import (
    "fmt"
    "strconv"
)

func main() {
    value := "123"
    // Convert string to int.
    number, _ := strconv.ParseInt(value, 10, 0)
    // We now have an int.
    fmt.Println(number)
    if number == 123 {
	fmt.Println(true)
    }
}

Output

123
true

Atoi. This function bears the same name as the one from the C standard library. In Go it invokes ParseInt with a base of 10 and a bit size of 0.

Tip:The Atoi call here is simpler than ParseInt. This gives it an advantage in readability in programs.

Golang program that uses Atoi

package main

import (
    "fmt"
    "strconv"
)

func main() {
    value := "456"
    // Use Atoi to parse string.
    number, _ := strconv.Atoi(value)

    fmt.Println(number)
    fmt.Println(number + 1)
}

Output

456
457

FormatInt. With this method, we convert an int to a string. This is the opposite conversion as ParseInt. With FormatInt, we must pass an int64 value—we cast in this example.
Golang program that uses strconv.FormatInt

package main

import (
    "fmt"
    "strconv"
)

func main() {
    value := 1055

    // Convert int to string with FormatInt.
    // ... First convert to int64.
    result := strconv.FormatInt(int64(value), 10)
    fmt.Println(result)
    if result == "1055" {
	fmt.Println(true)
    }
}

Output

1055
true

Itoa. This method converts an int into a string. It calls FormatInt with a base of 10. It also accepts a simple int, not an int64, so less casting may be required.

Note:Unlike ParseInt and Atoi, FormatInt and Itoa do not return an error value. They succeed on all possible arguments.

Golang program that uses Itoa, converts int to string

package main

import (
    "fmt"
    "strconv"
)

func main() {
    value := 700

    // Use Itoa on an int.
    result := strconv.Itoa(value)
    fmt.Println(result)

    // The string has 3 characters.
    fmt.Println(len(result))
}

Output

700
3

ParseInt benchmark. Often we need to convert a string into an integer. This benchmark compares ParseInt and Atoi. It converts "1234" into an integer with each method.

Result:No big performance differences were found. The methods performed about the same.

So:The best method to use is the one that has the correct behavior on all the data you want to convert.

Golang program that benchmarks ParseInt, Atoi

package main

import (
    "fmt"
    "strconv"
    "time"
)

func main() {
    t0 := time.Now()
    original := "1234";

    // Version 1: use ParseInt.
    for i := 0; i < 1000000; i++ {
	result, _ := strconv.ParseInt(original, 10, 0)
	if result != 1234 {
	    return
	}
    }

    t1 := time.Now()

    // Version 2: use Atoi.
    for i := 0; i < 1000000; i++ {
	result, _ := strconv.Atoi(original)
	if result != 1234 {
	    return
	}
    }

    t2 := time.Now()
    // Results of benchmark.
    fmt.Println(t1.Sub(t0))
    fmt.Println(t2.Sub(t1))
}

Results

15.637ms    ParseInt
15.625ms    Atoi


출처 : https://www.dotnetperls.com/parseint-go

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